Hypothesis Test for Balanced Load on 6 I/O Channels - N = 150

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The discussion centers on testing the hypothesis that the load on six I/O channels is balanced, given that the observed operations on each channel are uneven. The chi-square test is suggested as the appropriate method, with the formula χ² = (O-E)²/E, where O represents observed values and E represents expected values. The expected load for each channel is calculated as E = 150/6, resulting in an expected value of 25 operations per channel. Participants confirm that this approach is correct for testing the hypothesis at a 5 percent significance level. The conversation highlights the importance of correctly applying statistical methods to validate assumptions about system performance.
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Question : A computer system has 6 I/O channels and the system personnel are reasonably certain that the load on channels is balanced. If X is random variable denoting the index of the channel to which a given I/O operations is directed , that its pmf is assumed to be uniformly distributed. Out of N=150 I/O operation onserved, the number of operations directed to various channels were:
n0 = 22 ; n1 = 23 ; n2 = 29 ; n3 = 31 ; n4 = 26 ; n5 = 19

Test the hypothesis that the load on channels is balanced at 5 percent level of significance.

Solution
I have used the \chi2 = (O-E)2 / E

where O - obsevred and E is expected

Is this correct or should i be using some other method
 
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TomJerry said:
Question :

where O - obsevred and E is expected

Is this correct or should i be using some other method

You can use the chi square test \chi^2=\sum (O-E)^2/E Do you know how to get E?
 
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SW VandeCarr said:
You can use the chi square test \chi^2=\sum (O-E)^2/E Do you know how to get E?

I have taken all the E = \Sigmaxi/6

Is that correct?
 
TomJerry said:
I have taken all the E = \Sigmaxi/6

Is that correct?

Yes. If each I/O is taken as equally probable, 150/6=25=E.
 
SW VandeCarr said:
Yes. If each I/O is taken as equally probable, 150/6=25=E.

Thanks
 
If you're being sarcastic, why did you ask for confirmation in the first place?
 
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