I am doing a measurement in a system S with the apparatus A, in an

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I am doing a measurement in a system S with the apparatus A, in an entorn E. If the system is at [STRIKE]t0[/STRIKE] in Sithe measurement of the apparatus will be, after the decoherence time
 
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Is that a question? The state of the apparatus will depend on the interaction with the system.
What is "entorn"? Google suggest "environment", translated from catalan.
 


I don´t understand why the collapse of the wavefunction and the measure increase entropy. I start with a quantum system S and an aparattus A. The initial state of [ S+A ] is [(c_1|s_1>+c_2|s_2>+...)|a_0> ] and after the decoherence implies than apparatus end with a density operator [ p_1|1><a_1|+p_2|a_2><a_2|] where [p_n=|c_n|^2] ...His entropy goes up by shannon entropy to [-(p_1 ln (p_1)+p_2 ln (p_2)+...] that is [S>0] , in the premeasurement. But when collapse occurs , the final state of apparatus is [|a_n><a_n|] , for a random [n] , then it has entropy [S=0] . The entropy goes down and the same occurs to the system. Then why it is said that entropy goes up in a measurement?
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

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