- #1
Seda
- 71
- 0
Okay I know that (f+g)(x)= f(x) + g(x)
I need to prove (or disprove) that the sum of surjective funcitons is surjective.
However, I keep getting stuck up on one thing. If f(x) has the codomain Y and g(x) has the codomain Z, does (f+g)(x) have the codomain Y + Z (or Y U Z)? I can very easily state for this proof that for all y (and for all z) that there exists an x where f(x) = y (and that there exists an x where g(x)=z.)
I don't know how to follow this proof through to the sum function though. SOrry I'm not good at this theory/proof stuff.
I need to prove (or disprove) that the sum of surjective funcitons is surjective.
However, I keep getting stuck up on one thing. If f(x) has the codomain Y and g(x) has the codomain Z, does (f+g)(x) have the codomain Y + Z (or Y U Z)? I can very easily state for this proof that for all y (and for all z) that there exists an x where f(x) = y (and that there exists an x where g(x)=z.)
I don't know how to follow this proof through to the sum function though. SOrry I'm not good at this theory/proof stuff.