# I need to differentiate ln(x^4 sin(x^2) ). Help!

1. Jan 8, 2008

### rcmango

1. The problem statement, all variables and given/known data

need to differentiate:

f(x) = ln(x^4sinx^2)

2. Relevant equations

3. The attempt at a solution

just use ln 1/x and differentiate the sins and exponents to get whats below.

would this be the final form?
f'(x) = 4*(1/x) + 2*(cosx/(sinx)

2. Jan 8, 2008

### Shooting Star

Correct.

(Yes, I think he meant sin^2 x, i.e. (sin x)^2.)

Last edited: Jan 8, 2008
3. Jan 8, 2008

### HallsofIvy

Staff Emeritus
I presume that the first thing you did was use the laws of logarithms to simplify
$f(x) = ln(x^4sin^2x)$ to [itex]f(x)= 4 ln(x)+ 2 ln(sin(x)). Yes, the derivative is exactly what you say.