Let f(x) be the function f(x)=(2x-5)/(x^2-4)(adsbygoogle = window.adsbygoogle || []).push({});

I found the derivative to be (-2x^2+10x-8)/(x^2-4)^2

I then had to find the tangent at point (0, f(0)) to be y=-.5x+5/4

Im not sure if it is right from the graph i made on my calculater. Any help would be great!

**Physics Forums - The Fusion of Science and Community**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# I think I have it, please check

Loading...

Similar Threads - please check | Date |
---|---|

Possible mistake during differentiation? Please check | Nov 20, 2011 |

Rusty of Calculus: Please check this derivative for me | Jan 19, 2011 |

Please check my Derivative answers ! | Nov 17, 2010 |

Integral equation. Please check | Feb 5, 2010 |

Please check Limits problem | Sep 28, 2008 |

**Physics Forums - The Fusion of Science and Community**