Chris Davis
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I don't know if this formula already exists, but I think this may lead to finally finding the fail-proof square-root formula. What I've got now is this:
nx=nx-1+nx-1×(n-1)
I don't know if anyone else has actually discovered the above formula, but I do know that this has never failed for all the n/x combinations i have used. Let me know what you think!
nx=nx-1+nx-1×(n-1)
I don't know if anyone else has actually discovered the above formula, but I do know that this has never failed for all the n/x combinations i have used. Let me know what you think!