The discussion centers on calculating the coefficient of kinetic friction required to stop a 10,000 kg train traveling at 30 m/s over a duration of 30 seconds. Participants clarify that the friction force, which is essential for stopping the train, can be calculated using the equation Ff = μN = μmg. The calculated friction force is 10,000 N, leading to a coefficient of kinetic friction of approximately 0.102. The importance of understanding acceleration and the distinction between forces acting on the train is emphasized throughout the conversation.
PREREQUISITESStudents studying physics, particularly those focusing on mechanics, as well as educators looking to enhance their teaching of friction and motion concepts.
Well what did you get?Laura0901 said:I got one by using v=at
Why is that wrong? (Except of course you left the units off.) 10,000 NLaura0901 said:I used F=ma so: F=(10,000kg)(1)= 10,000
That's the force required to stop a 10,000kg train in 30 seconds if it was traveling at 30 m/sec. Friction is the force that's employed to stop the train.Laura0901 said:10,000 N is the force?
That seems reasonable.Laura0901 said:which equaled to .1020408163