The problem involves finding the coefficient of kinetic friction required to stop a train engine with a mass of 10,000 kg, initially traveling at 30 m/s, over a period of 30 seconds. The discussion centers around the forces acting on the train and the calculations needed to determine the friction involved in stopping it.
The discussion is ongoing with various interpretations being explored. Some participants have suggested using kinematic equations to find acceleration, while others express confusion about the forces at play. Guidance has been offered regarding the relationship between friction and the stopping force, but no consensus has been reached on the specifics of the calculations.
Participants note that the problem does not explicitly state certain values, such as acceleration, leading to confusion. There is also mention of the assumption that air resistance can be neglected in this context.
Well what did you get?Laura0901 said:I got one by using v=at
Why is that wrong? (Except of course you left the units off.) 10,000 NLaura0901 said:I used F=ma so: F=(10,000kg)(1)= 10,000
That's the force required to stop a 10,000kg train in 30 seconds if it was traveling at 30 m/sec. Friction is the force that's employed to stop the train.Laura0901 said:10,000 N is the force?
That seems reasonable.Laura0901 said:which equaled to .1020408163