I with this STATISTICS problem that deals with Chebyshev's theorem.

rdapaul
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the heights of adult men at Suny Rockland have mean heights of 63.6 and a standard deviation of 2.5. What does Chebyshev's theorem tell us about the percentage of men whose heights are between 58.6 in. and 68.6 in.?
 
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Since 58.6 and 68.6 are equally distant from the mean, find the number of standard deviations 68.6 is above the mean and then apply Chebyshev's theorem.
 
rdapaul said:
the heights of adult men at Suny Rockland have mean heights of 63.6 and a standard deviation of 2.5. What does Chebyshev's theorem tell us about the percentage of men whose heights are between 58.6 in. and 68.6 in.?

In such type of questions, the best way to handle them is to ask yourself what formula you require to obtain the interval values. This formula is: lower value=mean-k(s.d.) or upper value=mean+k(s.d.). Once you solve for k in either the two equations, you may use the value obtained to get the percentage using Chebyshev's Theorem.
 

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