- #1
shredder666
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If I have a piece of ice melting in a water and eventually comes to equilibrium with the water... The the total enthalpy change includes the following right?
Heat absorbed for ice to get to 0 degrees
Heat absorbed for ice to melt to water
Heat absorbed for the melted ice water to come to equilibrium with the water
And the above is equal to the heat lost by the water surroundings... right?
For people that likes math :P
The total enthalpy change can be represented by the following right?
mice× Cice× ΔTice + niceΔHfus°+ mice× cwater× ΔTwater = mcal × Cwater× ΔTcal
Heat absorbed for ice to get to 0 degrees
Heat absorbed for ice to melt to water
Heat absorbed for the melted ice water to come to equilibrium with the water
And the above is equal to the heat lost by the water surroundings... right?
For people that likes math :P
The total enthalpy change can be represented by the following right?
mice× Cice× ΔTice + niceΔHfus°+ mice× cwater× ΔTwater = mcal × Cwater× ΔTcal