B If an object runs an infinite distance in universe....?

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An object at an infinite distance from Earth does not possess infinite potential energy, as potential energy calculations depend on proximity to a gravitational source. The equation E=mgh is only an approximation applicable near the Earth's surface, where height h is much smaller than the Earth's radius. The correct formula for potential energy at a distance R from the Earth's center is E = -GMm/R, which shows that even an object falling from infinity results in a finite energy gain. The concept of infinity is a useful mathematical tool but does not translate to physical reality in this context. Thus, potential energy remains finite regardless of the object's initial distance.
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...(after infinite distance) falls into earth, would exist infinite potential energy if E=mgh and h is infinite?
 
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Since it would take an infinite amount of time, it would never happen.

If you are asking whether any object at an infinite distance from the Earth has infinite potential energy, the answer is no, absolutely not and it is easy to see why if you study "escape velocity".
 
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Irrelevant, anything at infinity has no influence on the observable universe
 
Chronos said:
Irrelevant, anything at infinity has no influence on the observable universe
Everybody remember infinity is a "concept" (a very useful one) but not a physical "thing!"
 
Noduagga said:
...(after infinite distance) falls into earth, would exist infinite potential energy if E=mgh and h is infinite?

I think the real answer to your question is that E = mgh is just an approximation for small values of h near the Earth's surface. The full equation for the potential energy of an object of mass m at a distance R from the Earth's center is that E = -GMm/R, where M is the mass of the Earth, and G is Newton's constant of gravitation. Near the Earth's surface, R is approximately constant, so we can write
R = R0 + h where h <<R. Then the potential energy can be approximated by $$ E=-\frac{GMm}{R0+h} \approx -\frac{GMm}{R0}(1-h/R0) = -\frac{GMm}{R0} +\frac{GM}{R0^2} mh$$ Then, for changes in the potential energy, we ignore the first term, since it doesn't change, and we call the quantity $$\frac{GM}{R0^2}$$ g, and then you have your formula E=mgh. So if you use the full formula, even an object falling from infinity only gains an amount of energy equal to $$\frac{GMm}{R0}$$, which is a finite quantity.
 
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Noduagga said:
...(after infinite distance) falls into earth, would exist infinite potential energy if E=mgh and h is infinite?
E=mgh is only an approximation, valid for objects near the Earth's surface.
 
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