If F(x,y)=<M(x,y),N(x,y)> is a vector field on the plane?

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SUMMARY

The discussion centers on the vector field F(x,y) = and its components M(x,y) and N(x,y), which are differentiable functions. It is established that the vector field cannot be conservative because the condition (∂N(x,y)/∂x) – (∂M(x,y)/∂y) = 1-x indicates a non-zero curl. The integral ∫F.dr over the curve C defined by x^2+y^2=1 can be computed using Green's Theorem, which relates the line integral around a simple closed curve to a double integral over the region it encloses.

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sarahkelly
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its components M(x,y) and N(x,y) are differentiable functions that satisfy (∂N(x,y)/∂x) – (∂M(x,y)/∂y) = 1-x.

a. is it possible for the vector field to be conservative? Explain.


b. Let C be x^2+y^2=1 centered at the origin traced counter clockwise. compute the integral ∫F.dr



Since, the partial derivatives don't equal each other, they're not conservative. But how should I go about calculating this line integral?
 
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Well, first before we help you, you should say what you've gotten so far. Though based off the information given, I'll guess you know about Green's Theorem, in which case this is a fairly easy problem.
 
sarahkelly said:
its components M(x,y) and N(x,y) are differentiable functions that satisfy (∂N(x,y)/∂x) – (∂M(x,y)/∂y) = 1-x.

a. is it possible for the vector field to be conservative? Explain.b. Let C be x^2+y^2=1 centered at the origin traced counter clockwise. compute the integral ∫F.dr
Since, the partial derivatives don't equal each other, they're not conservative. But how should I go about calculating this line integral?
You are not give F but you are given (∂N(x,y)/∂x) – (∂M(x,y)/∂y) = 1-x. Use Green's theorem.
 

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