- #1
mr_coffee
- 1,629
- 1
ello ello!
I'm pretty sure this is right but not 100%. Directions are as follows:
GIve a reason for your answer in each of 1-13. Assume that all variables represent integers.
If n = 4k + 3, does 8 divide n^2-1? Here is my answer:
No. n^2-1 = (4k+3)^2-1 = (4k+3)(4k+3)-1 = (16k^2+24k+9)-1 = 16k^2+24k+8 = 16(k+1/2)(k+1). K+1 is an integer but k+1/2 is not necessarily an integer, because 1/2 is not an integer.
Is my reasoning correct? thanks!
I'm pretty sure this is right but not 100%. Directions are as follows:
GIve a reason for your answer in each of 1-13. Assume that all variables represent integers.
If n = 4k + 3, does 8 divide n^2-1? Here is my answer:
No. n^2-1 = (4k+3)^2-1 = (4k+3)(4k+3)-1 = (16k^2+24k+9)-1 = 16k^2+24k+8 = 16(k+1/2)(k+1). K+1 is an integer but k+1/2 is not necessarily an integer, because 1/2 is not an integer.
Is my reasoning correct? thanks!