If so, you can differentiate it with respect to Vd to prove Rd=\frac{Vt}{Id}.

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differentiate requested please

i want to differentiate this equation Id=IsxexponentVd/Vt with respect to Vd to prove Rd=Vt/Id
 
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Remember that the derivative with respect to x of e^(kx) is ke^(kx) using the chain rule. Also remember that V=iR.
 


Does your equation look like as,
Id=Ise\frac{V<sub>d</sub>}{V<sub>t</sub>} ?
 
Thread 'Direction Fields and Isoclines'

Thread 'Direction Fields and Isoclines'

I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
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