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I'm doing something wrong

  • #1
[SOLVED] I'm doing something wrong...

1. A red laser with a wavelength of 650 nm and a blue laser with a wavelength of 450 nn emit laser beams with the same light power. How do their rates of photon emission compare? Answer this by computing R[tex]_{red}[/tex] / R[tex]_{blue}[/tex]



2. P = Rhf = dNhf / dt = dE[tex]_{light}[/tex] / dt
R = dN / dt
E[tex]_{light}[/tex] = Nhf, where N is the number of photons
f = c / [tex]\lambda[/tex]
h = 6.624E-32 Js




3. I have the f[tex]_{red}[/tex] = 4.62 x 10[tex]^{14}[/tex] s
and f[tex]_{blue}[/tex] = 6.67 x 10[tex]^{14}[/tex] s , it says their Powers are the same, so I go ahead and went and equaled:

P[tex]_{red}[/tex] to P[tex]_{blue}[/tex], which is:


P[tex]_{red}[/tex]h[tex]_{red}[/tex]f[tex]_{red}[/tex] = P[tex]_{blue}[/tex]h[tex]_{blue}[/tex]f[tex]_{blue}[/tex]

but I am tired and can't see the relevance, because when I multiplied times h [in Js] and then I divide like explained, I get .6925, and the ANSWER is 1.44.

Help? Please?
 

Answers and Replies

  • #2
berkeman
Mentor
56,634
6,532
Since red photons carry less energy per photon, there will need to be more of them. You just got your answer upside-down.

Just use your equation for E = Nhf, and be sure to take the ratio in the correct direction.
 
  • #3
Chi Meson
Science Advisor
Homework Helper
1,789
10
1. A red laser with a wavelength of 650 nm and a blue laser with a wavelength of 450 nn emit laser beams with the same light power. How do their rates of photon emission compare? Answer this by computing R[tex]_{red}[/tex] / R[tex]_{blue}[/tex]



2. P = Rhf = dNhf / dt = dE[tex]_{light}[/tex] / dt
R = dN / dt
E[tex]_{light}[/tex] = Nhf, where N is the number of photons
f = c / [tex]\lambda[/tex]
h = 6.624E-32 Js




3. I have the f[tex]_{red}[/tex] = 4.62 x 10[tex]^{14}[/tex] s
and f[tex]_{blue}[/tex] = 6.67 x 10[tex]^{14}[/tex] s , it says their Powers are the same, so I go ahead and went and equaled:

P[tex]_{red}[/tex] to P[tex]_{blue}[/tex], which is:


P[tex]_{red}[/tex]h[tex]_{red}[/tex]f[tex]_{red}[/tex] = P[tex]_{blue}[/tex]h[tex]_{blue}[/tex]f[tex]_{blue}[/tex]

but I am tired and can't see the relevance, because when I multiplied times h [in Js] and then I divide like explained, I get .6925, and the ANSWER is 1.44.

Help? Please?
Yes the answer is 1.44.

You got confused because you plugged in your number way too soon. Consider this:

Only the wavelengths are important. Obviously "R" here is used as "N," th number of photons per second? Well, P=P, you got that, and P=(Rhf)/t and f =c/ lamda.

Just substitute, see what cancel out, and use what you are left with.
 
  • #4
49
0
I double checked the math, looks good.
 
  • #5
Ok....that was...really weird, I guess I somehow reversed wavelengths? I simply did the reciprocal and it worked, thanks all!
 

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