I'm trying to show a function has non-uniform continuity

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Discussion Overview

The discussion centers on demonstrating that a specific function, f(x) = x³, has non-uniform continuity. Participants are exploring the conditions under which two sequences can be found that approach each other while their function values do not converge to the same limit.

Discussion Character

  • Exploratory, Mathematical reasoning

Main Points Raised

  • One participant seeks to find two sequences (x_n) and (y_n) such that |(x_n) - (y_n)| approaches zero.
  • Another participant questions the convergence points of the sequences x_n and y_n.
  • A third participant clarifies that |x_n - y_n| must converge to 0, while |f(x_n) - f(y_n)| must converge to some real number.
  • A later reply proposes specific sequences x_n = 1/n and y_n = 1/n², asserting that both converge to zero and that the difference |x_n - y_n| approaches zero as n approaches infinity.
  • This same reply calculates |f(x_n) - f(y_n)| and suggests it also approaches zero as n approaches infinity.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the existence of suitable sequences that demonstrate non-uniform continuity, and the discussion includes various interpretations and proposals regarding the sequences.

Contextual Notes

There are unresolved assumptions regarding the conditions under which the sequences are defined and the implications of their convergence on the continuity of the function.

rbzima
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I'm trying to show a function has non-uniform continuity, and I can't seem to think of 2 sequences (xn) and (yn) where |(xn) - (yn)| approaches zero, where f(x) = x3. Can anyone think of two sequences?
 
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Where are the two sequences x_n and y_n separately supposed to converge?
 
sutupidmath said:
Where are the two sequences x_n and y_n separately supposed to converge?

|x_n - y_n| need to converge to 0.
|f(x_n ) - f(y_n)| needs to converge to some real number, where f(x) = x^3
 
I don't know if i am getting you right, but if there are no additional conditions imposed there, then i think the following would work

x_n=\frac{1}{n} y_n=\frac{1}{n^2} these both converge to zero and also

let |a_n=x_n-y_n=\frac{n-1}{n^{2}}|-->0, \ \ as \ \ n-->\infty

Also:

|f(x_n)-f(y_n)=\frac{1}{n^{3}}-\frac{1}{n^6}=\frac{n^3-1}{n^6}|-->0, \ \ as \ \ \ n-->\infty
 

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