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Impedance matching/purely resistive

  1. Oct 3, 2008 #1
    is this true?


    To prevent all reflections of the signal back into the source, the load (which must be totally resistive) must be matched exactly to the source impedance (which again must be totally resistive)

    what if you divide the wire into 2 parts. isnt the impedance of each complex? so shouldnt there be reflection at the boundary? obviously that makes no sense. what am i missing.
  2. jcsd
  3. Oct 3, 2008 #2
  4. Oct 3, 2008 #3
    ok. i get it.

    each segment of wire does have exactly the same impedance at all frequencies but a load will generally not have exactly the same impedance at all frequencies.
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