is this true?(adsbygoogle = window.adsbygoogle || []).push({});

http://en.wikipedia.org/wiki/Impedance_mismatch

To prevent all reflections of the signal back into the source, the load (which must be totally resistive) must be matched exactly to the source impedance (which again must be totally resistive)

what if you divide the wire into 2 parts. isnt the impedance of each complex? so shouldnt there be reflection at the boundary? obviously that makes no sense. what am i missing.

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# Impedance matching/purely resistive

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