- #1
lLovePhysics
- 169
- 0
Hello there! Please help me relieve my confusion. Thanks!
For [tex] \frac{d}{dx}[y^{3}] [/tex], why do you need to use the chain rule on this equation? Basically, the chain rule is used on almost every function right? It is just that we do not see the dx/dx since it equals one, for example:
[tex] f(x)=\sin{x}[/tex] In full notation, its derivative is suppose to look like this right?:
[tex] f'(x)=(\cos{x}) \frac{dx}{dx}[/tex]. Then the derivative of x with respect to x is just 1.
For [tex] \frac{d}{dx}[y^{3}] [/tex], why do you need to use the chain rule on this equation? Basically, the chain rule is used on almost every function right? It is just that we do not see the dx/dx since it equals one, for example:
[tex] f(x)=\sin{x}[/tex] In full notation, its derivative is suppose to look like this right?:
[tex] f'(x)=(\cos{x}) \frac{dx}{dx}[/tex]. Then the derivative of x with respect to x is just 1.