Implicit Differentiation z=f(x/y) meaning

xoxomae
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Mod note: Moved from the Homework section
1. Homework Statement

This might seem like a stupid question but I'm unsure what z= ƒ(x/y) means? I'm not sure how I would find ∂z/∂x , ∂z/∂y just from this statement either.

Thank you

Homework Equations

The Attempt at a Solution

 
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xoxomae said:

Homework Statement


This might seem like a stupid question but I'm unsure what z= ƒ(x/y) means? I'm not sure how I would find ∂z/∂x , ∂z/∂y just from this statement either.

Thank you

Homework Equations

The Attempt at a Solution


You could try taking ##f## to be some simple function. For example ##f(X) = X^2##, where I've used ##X## to define the function to avoid confusion with ##x, y##.
 
xoxomae said:
Mod note: Moved from the Homework section
1. Homework Statement

This might seem like a stupid question but I'm unsure what z= ƒ(x/y) means? I'm not sure how I would find ∂z/∂x , ∂z/∂y just from this statement either.
It means that z is a function of the quotient x/y. For example, ##z = (x/y)^2 + 3(x/y)##

To find the partial derivatives, you'll need to use the chain rule.
 
I'm sorry, I'm just really unsure how to apply the chain rule. So is ∂z/∂t = ∂/∂x(x/y) * F' ? But I'm unsure how to find all the other ones. I have the solutions attached to this post but I have no idea how to get them.
Thank You
 

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xoxomae said:
I'm sorry, I'm just really unsure how to apply the chain rule. So is ∂z/∂t = ∂/∂x(x/y) * F' ? But I'm unsure how to find all the other ones. I have the solutions attached to this post but I have no idea how to get them.
Thank You
What are ##t## and ##F##?

Can you calculate ##\frac{\partial z}{\partial x}## if ##z=f(u(x,y))## where ##u## is a function of ##x## and ##y##?
 
So i would let u=x/y so then

$$ \frac{\partial z}{\partial x} = \frac{\partial z }{\partial u} \frac{\partial u }{\partial x} = \frac{f'}{y} $$

cause I'm guessing $$\frac{\partial z }{\partial u} = f'$$ or am i completely wrong?
 
That's right.
 

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