Improve Your Test Preparation with Expert Help - Math Questions Solved

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SUMMARY

This discussion focuses on improving test preparation for math questions, specifically involving functions and trigonometry. The user seeks assistance with the reciprocal function of y = x^2 - 2x - 8 and the vertical asymptotes, noting confusion regarding parabolas and asymptotes. Additionally, the user requests help in calculating sin(a+b) given cos(a) = 4/5 and sin(b) = 12/13, with detailed steps provided for finding the necessary trigonometric values. The final result for sin(a+b) is confirmed as 53/65.

PREREQUISITES
  • Understanding of quadratic functions and their properties
  • Knowledge of trigonometric functions and identities
  • Familiarity with the concept of asymptotes in functions
  • Ability to work with angles in different quadrants
NEXT STEPS
  • Study the properties of reciprocal functions in algebra
  • Learn about vertical asymptotes and their applications in rational functions
  • Explore trigonometric identities, particularly the sine addition formula
  • Practice solving problems involving angles in different quadrants
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Students preparing for math tests, educators seeking to enhance their teaching methods, and anyone looking to improve their understanding of functions and trigonometry.

Prents
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I'm currently working through a self taught program, coming up to my first test and have found a review that works well for what I need, I'm stuck on several questions and any help you can provide on any of them will greatly help!

1. Consider the function: y = x^2 - 2x - 8
a) State the equation of the reciprocal function
b) Write the equation of the vertical asymptotes (I find this to be a parabola which can't have asymptotes which is my struggle)

2. If "a" is an angle in Quadrant 4 where cos a = 4/5, and "b" in an angle with sinb= 12/13 where 90 degrees< b < 180 degrees.
a) What is the exact value of sin(a+b)?

Any help you can provide or links to pages or videos will greatly help! Thank you!
 
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2a:

Expanding sin(a+b) gives sin(a)cos(b) + cos(a)sin(b). So we need to find cos(b) and sin(a).

Since angle a is in quadrant 4, sin(a) is negative. So it is -\sqrt{1 - \left(\frac{4}{5}\right)^2}, or -1/5.

Since angle b is in quadrant 2, cos(b) is negative. So it is -\sqrt{1 - \left(\frac{12}{13}\right)^2}, or -5/13.

Simplifying sin(a+b) gives -\frac{1}{5} \cdot -\frac{5}{13} + \frac{4}{5} \cdot \frac{12}{13}, or \boxed{\frac{53}{65}}.
 

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