The statement I read is: Because of the way that series-wound generators are constructed, they possess poor voltage regulation capabilities. For example, as the load voltage increases, the current through the field coils also increases. This induces a greater emf that, in turn, increases the generator's output voltage. Therefore, when the load increased, voltage increases; likewise, when the load decreases, voltage decreases. Questions: What is meant by load voltage and output voltage? Is load voltage simply the voltage drop in the circuit? Is it saying if you at resistance, like an additional light bulb, to the circuit. The total voltage drop across all the resistance (light bulbs) in the circuit will increase? As I understand a Dc circuit with a battery, increasing resistance in the circuit does not change the voltage drop nor the battery's output voltage according to ohms law. And current decreases linearly as resistance increases. Then, in a generator, how does the current increase when resistance (light bulbs) in the circuit increase? Or how does the magnetic field in the field coil increase when light bulbs are added? One possibility I am guessing is that increasing the resistance in the circuit, actually lowers the circuit's current as well (just as in a Dc circuit with a battery as the source voltage). However, when the current is reduced in the field windings, it changes the inductive reactance in the field winding coils in some way that actually allows for a stronger magnetic field, which increases the amplitude of the output voltage and also forces the generator rotor to spin at a faster rate, thus producing a higher frequency, thus more voltage output. Are the events I just described anything similar to what the statement in the provided text is saying? Any and all feedback would be greatly appreciated. Thank you. P.S. If the concepts could be described in non calculus terms, I would be ever more appreciative. Much thanks.