In QM: How to derive <x|f> from f_n(x)?

[mishla]

Homework Statement

If you have a function f_n(x), how do you get the equivalent representation <x|f>?

Homework Equations

I have a system with a given Hamiltonian (not in matrix-form), from which I derived the specter of energy eigenvalues E_n, and the corresponding energy eigenfunctions f_n(x). However, I am asked to derive the eigenstates in the form <x|f> also, how do I do that?

The Attempt at a Solution

 

[gabbagabbahey]

f_n(x) is equivalent to \left&lt; x | f_n \right&gt;

 

[HallsofIvy]

By the way, it is "spectrum", not "specter". Although, with Halloween coming, it may be appropriate!

As gabbagabbahey said, f_n(x) IS \left&lt; x | f_n \right&gt; . <x, f> is the sum of \left&lt; x | f_n \right&gt; over all n.

 

[mishla]

Thanks for the answers! So what is then meant by

“When you have found the spectrum of energy-eigenvalues, find the corresponding energy-eigenstates, both the abstract number basis and the concrete position-representation <x|f>.”?

Is “the abstract number basis” the same as f_n(x) (the one I have found)? And is “the concrete position representation <x|f>” then the sum of f_n(x) over all n?

And thanks for the correction of my misspelling, English is not my mother tounge…

 

[gabbagabbahey]

Suppose one of the energy eigenstates in some abstract basis was

|f_1 \rangle =\frac{1}{\sqrt{2}} |x \rangle -\frac{i}{\sqrt{2}} |y \rangle

Then in the concrete basis it would be f_1(x)=\langle x|f_1 \rangle=\frac{1}{\sqrt{2}}