In SSB, why shifting a field suffices to pick a corresponding vaccum?

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Discussion Overview

The discussion revolves around the concept of shifting a field in the context of \(\phi^4\) theory with \(Z_2\) breaking, specifically addressing how this shift relates to selecting a corresponding vacuum state. The scope includes theoretical exploration and conceptual clarification regarding ground states and vacuum selection.

Discussion Character

  • Exploratory
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant notes that before the shift, the expectation value \(\langle\phi\rangle=0\) due to symmetry, and after the shift, \(\langle\phi\rangle\neq0\) indicates a selection of a vacuum from two possibilities.
  • Another participant argues that the shift is not an ad hoc procedure but is necessary to identify a true ground state, suggesting that expanding around \(\langle\phi\rangle=0\) leads to a false vacuum scenario.
  • A follow-up question is posed regarding why the shift results in picking the correct vacuum state.
  • It is mentioned that the nature of the ground state with \(\langle\phi\rangle\neq 0\) is derived from the Lagrangian.
  • Clarification is sought on why the shift specifically leads to selecting the right vacuum state.

Areas of Agreement / Disagreement

Participants express differing views on the implications of the field shift and its role in vacuum selection, indicating that multiple competing perspectives remain without a consensus on the underlying reasons for the observed outcomes.

Contextual Notes

The discussion does not resolve the assumptions regarding the nature of the Lagrangian or the implications of shifting the field, leaving these aspects open for further exploration.

ingenue
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Consider the simplest [tex]\phi^4[/tex] with [tex]Z_2[/tex] breaking. Before the shift, [tex]\langle\phi\rangle=0[/tex] by symmetry. After the shift, the vev of the shifted field is zero, which means [tex]\langle\phi\rangle\neq0[/tex], which in turn means we have picked the corresponding vacuum out of two possibilities. However, through the calculation of path integral, shifting a field by a constant only has done nothing as to fixing the boundary condition. Then why did this happen?
 
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"The shift" isn't an ad hoc procedure. It happened to pick out a true ground state. With [tex]\langle\phi\rangle=0[/tex], you're trying to perturbatively expand around a false vacuum, and it ain't going to work.
 
daschaich said:
"The shift" isn't an ad hoc procedure. It happened to pick out a true ground state. With [tex]\langle\phi\rangle=0[/tex], you're trying to perturbatively expand around a false vacuum, and it ain't going to work.

that's exactly why I'm asking. why did it happen to do this?
 
Why did it happen that the ground state has [tex]\langle\phi\rangle\neq 0[/tex]? That comes from the lagrangian.
 
No, I meant why did it happen to pick out the right vacuum?
daschaich said:
Why did it happen that the ground state has [tex]\langle\phi\rangle\neq 0[/tex]? That comes from the lagrangian.
 

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