In the limit as A --> ∞, what does the function become?

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SUMMARY

The function fA(x) = A for |x| < 1/A and 0 for |x| > 1/A approaches the Dirac delta function as A approaches infinity. The integral of fA(x) over the entire real line equals 2, indicating that the correct representation is 2δ(x), as the Dirac delta function is a distribution rather than a traditional function. This distinction is crucial for understanding the behavior of fA(x) in the limit.

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Homework Statement


The function is fA(x) = A, |x| < 1/A, and 0, |x| > 1/A

Homework Equations


δ(x) = ∞, x=1, and 0 otherwise

The Attempt at a Solution


I think the answer is the Dirac delta function, however I noticed that if you integrate fA(x) between -∞ and ∞ you get 2, which if I remember rightly to be a Dirac delta function this should be 1? So perhaps the answer is 2 x δ(x)?
I'm not sure what's correct, so any help would be greatly appreciated, thank you!
 
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2 times the delta distribution (it is not a function), correct.
Avoid using x as variable and multiplication sign at the same time, please. * is the typical multiplication sign in ascii.
 
mfb said:
2 times the delta distribution (it is not a function), correct.
Avoid using x as variable and multiplication sign at the same time, please. * is the typical multiplication sign in ascii.
Great thank you, and apologies, I'm aware it's not a function but a measure, but alas my lecturer uses the term function and so it's stuck with me. As for x for multiply, laziness is all, sorry... thanks again, much appreciated :)!
 

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