Increasing electric potential and electric field

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SUMMARY

The discussion centers on the relationship between electric potential difference (ΔV) and electric field (E) in the context of physics. The user correctly applies the formula ΔV = -EΔx, calculating an electric field strength of 1.5 x 10^3 N/C. The conversation highlights the importance of vector direction, suggesting that ΔV = -EΔz may be more appropriate depending on the orientation of the electric field vector in the XY plane.

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  • Understanding of electric potential difference (ΔV)
  • Familiarity with electric field concepts (E)
  • Knowledge of vector components in physics
  • Basic algebra for manipulating equations
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mcastillo356
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Homework Statement
Let's suppose an increasing electric potential along the positive Z axis, such that the XY plane is at ##V=0##. If the potential increases by 15 V every centimeter, calculate the module and direction of the electric field. Draw the coordinate system and vector representing the electric field
Relevant Equations
##\Delta{V}=-E\Delta{x}##
Hello everybody!
I want to check out if I've solved correctly:
##\Delta{V}=-E\Delta{x}##
##\dfrac{\Delta{V}}{\Delta{x}}=-E##
##\dfrac{15\;V}{10^{-2}\;m}=-E##
##1,5\times{10^3}\;N/C=-E##
##\vec{E}## direction it's oriented into the XY plane
Thanks!
 
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Looks good. But, would it be more appropriate to write ##\Delta V = -E \Delta z## rather than ##\Delta V = -E \Delta x##?
 
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Yes!. It's the direction of the E vector. Thanks a lot!
 

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