Increasing speed by 5 mph saves 10 mins?

  • Thread starter Thread starter KingNothing
  • Start date Start date
  • Tags Tags
    Increasing Speed
AI Thread Summary
To determine the distance and speeds involved when increasing speed by 5 mph saves 10 minutes, two equations are established based on the relationship between speed, time, and distance. The first equation represents the initial trip, while the second accounts for the increased speed and reduced time. By substituting the known variables, the equations can be set equal to each other, leading to a solvable format. The discussion emphasizes the importance of correctly manipulating these equations to find the desired values. Ultimately, the problem illustrates the mathematical principles governing speed and time in travel scenarios.
KingNothing
Messages
880
Reaction score
4
If a person drives the same distance twice, and saves 10 mins by driving 5mph more the second time, what is the distance and the speeds?
 
Physics news on Phys.org
Speed * time = distance.

Set up two equations -- one for each trip -- and notice that the distances are equal. Thus, you can set the equations equal to each other, arriving at:

Speed1 * time1 = speed2 * time2.

You know that speed2 = speed1 + 5, and that time2 = time1 - 10.

Put these equations together and solve for distance...

- Warren
 
Can you work through it for me? I keep getting time1=10+2*speed1...
 
KingNothing said:
Can you work through it for me? I keep getting time1=10+2*speed1...
Write out your full two equations and show how you are trying to solve them.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
3
Views
850
Replies
21
Views
1K
Replies
4
Views
7K
Replies
32
Views
1K
Replies
16
Views
2K
Replies
1
Views
2K
Replies
9
Views
1K
Replies
8
Views
3K
Replies
3
Views
1K
Back
Top