Independent or paired? (Statistics)

AI Thread Summary
The discussion centers on whether the repair cost estimates from two appraisers for the same car damages are independent or paired. It concludes that the samples are paired because the measurements are taken from the same vehicles, indicating a dependency between the appraisals. A 95% confidence interval for the mean difference in repair costs is mentioned, with a request for clarification on its significance. The conversation emphasizes that trained appraisers' values are not purely random, reinforcing the paired nature of the data. Understanding these concepts is crucial for accurate statistical analysis in similar scenarios.
kash-k
Messages
17
Reaction score
0
I was just doing some revision and came across a sticky thought -

Suppose you got two appraisers for 9 car damages and both give different prices for the repair. Would the samples be independent or paired? I reckon it's paired but I can't put a reasoning behind it!

And I also did a 95% confidence interval for the mean difference of repair costs but what is the damn meaning of the result?!

Thanks guys!
 
Physics news on Phys.org
Do you believe that the value a (presumably trained) appraiser comes up with for car damage is purely random? If so then they are independent.
 
Since the measurements are on the same vehicles, they are dependent - this is an example of a matched-pair (a.k.a. paired-difference) data collection.
 

Thread 'Finding the number of ways to arrange identical balls in a circle (3 different colors)'

I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
View full post »

Thread 'Greatest possible value of a constant in polynomial'

Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
View full post »

Similar threads

I Is Unbiasedness in Estimation Truly Reflective of Population Parameters?
Replies
9
Views
2K
MHB Confidence interval of difference
Replies
1
Views
1K
B Experiment to test for causality
Replies
30
Views
2K
MHB IHave no idea how to solve any os these.
Replies
4
Views
1K
I Does Time-Symmetry Imply Retrocausality? How does the Quantum World Say “Maybe”?
3
Replies
119
Views
2K
MHB Are These Statistics Practice Answers Correct?
Replies
1
Views
2K
A Defining a Symmetry Statistic to test for Normality?
Replies
4
Views
2K
Optimal linear combination of independent estimates for minimizing variance
Replies
1
Views
2K
Confusion between z and t values
Replies
5
Views
3K
Confidence intervals for ratios of variances and other confusing stats
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top