Induced Magnetic Field: Moving Arbitrary Conductors in Nonuniform Fields

AI Thread Summary
When an arbitrary conductor moves through a nonuniform magnetic field, the induced field in the conductor is primarily an electric field, not a magnetic field. The concept of susceptibility is deemed irrelevant in this context. The induced electromotive force (EMF) can be calculated using the integral of the electric field along the conductor's path. Specifically, for a conductor moving with velocity v in a varying magnetic field, the EMF is given by the integral of the cross product of velocity and magnetic field around the loop. Understanding these principles is crucial for analyzing induced fields in dynamic magnetic environments.
vibe3
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If I have some arbitrary conductor moving through a (nonuniform) magnetic field \mathbf{B}(\mathbf{r}), would the induced field in the frame of the conductor be something like:
<br /> \mathbf{B}_{IND}(\mathbf{r}) = T \mathbf{B}(\mathbf{r})<br />
where T is some diagonal matrix whose entries are related to the susceptibilities of the conductor?

I'm having trouble finding any reference on this other than a wire moving through a uniform field with some velocity.
 
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vibe3 said:
If I have some arbitrary conductor moving through a (nonuniform) magnetic field B(r)B(r)\mathbf{B}(\mathbf{r}), would the induced field in the frame of the conductor be something like:
BIND(r)=TB(r)BIND(r)=TB(r)​

The induced field in the conductor is an electric field not a magnetic field. Susceptibility of the conductor is irrelevant.

The voltage or EMF = ∫C E⋅dl where E is the electric field in the conductor and dl is an elemental conductor length.
For a varying magnetic field B(x,y,z) and a conductor C moving with velocity v the
EMF = ∫C (vxB)⋅dl where the integral is taken around the conducting loop C.
 
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