Inductance of a Trace: Qualitative Analysis

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SUMMARY

The inductance of a PCB trace is greater on the narrower side due to increased current density, as described by the equation J = I / A. When the trace tapers from a wider section to a narrower section, the same amount of current passing through a smaller area results in a higher current density. This higher current density leads to increased inductance because the narrower trace can store more magnetic energy. The inductance behavior can be qualitatively understood by considering that a wider trace behaves like multiple narrower traces in parallel, which reduces overall inductance.

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roeb
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If I have a trace on a PCB that is wider on the left side and then tapers down to a narrower trace on the right side, why is it that the inductance is greater on the narrower side? I realize there are equations that describe this behavior but I'm just trying to get a qualitative understanding of this.

I can see how the capacitance on the wider side would be greater than the capacitance on the narrower side (due to area) but I can't quite see why the inductance is greater on the narrower side. I know that the current density J = I / A and given that we are pushing the same amount of current through the trace, the current density would be greater in the trace with less area. Will a higher current density result in a higher indutance -- is this because it is able to store more energy?
 
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If the trace is twice as wide, it is like having two single-width traces in parallel. The inductance of the parallel combination is 1/2 that of the single width trace.
 

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