Inductive Circuit and Frequency

[ah4p]

Homework Statement

A resistor and a capacitor are connected in series to a variable frequency supply. A voltmerter is connected across the inductor and another across the resistor. The supply voltage is kept constant as frequency of supply is increased.
State and explain the changes in the readings on voltmeters across the inductor and across the resistor

Homework Equations

current is inversely proportional to frequency in an inductive circuit

V=IR

The Attempt at a Solution

I thought across the inductor V decreases since I will decrease as a result of frequency increasing

therefore to keep total V constant the V across the resistor will increase

4. Actual ANSWER

the answer however is V across resistor increases because Inductive reactance increases & Current decreases

so V across inductor decreases

I've never been taught what inductive reactance means?

can anyone explain why this is the answer
thank you very much in advance :)
my prelim is on MOnday :( and I'm so failing

 

[lightgrav]

First phrase says R series C ... the rest talks about L ... are there all 3, or just L?
reactance "X" is a "generalized resistance" ... how much (volt-wise) does the device "react" to conducting AC current?
V_(AC) = I X
for a Resistor, X_R = R , no matter what the frequency is.
for a capacitor, X_C = 1/ωC ... since small amount of charge collects in short time, at high frequency.
for an inductor, X_L = ωL ... since the current changes more rapidly at high frequency.


You have R series L, so they have the same current;
what happens to the Resistor's voltage, if the current is limited by the inductor (at high frequency)?

 

[ah4p]

First phrase says R series C ... the rest talks about L ... are there all 3, or just L?
reactance "X" is a "generalized resistance" ... how much (volt-wise) does the device "react" to conducting AC current?
V_(AC) = I X
for a Resistor, X_R = R , no matter what the frequency is.
for a capacitor, X_C = 1/ωC ... since small amount of charge collects in short time, at high frequency.
for an inductor, X_L = ωL ... since the current changes more rapidly at high frequency.You have R series L, so they have the same current;
what happens to the Resistor's voltage, if the current is limited by the inductor (at high frequency)?

oh it would increase since the electrons require more energy to move through it??

thanks for replying

 

[NascentOxygen]

4. Actual ANSWER

the answer however is V across resistor increases because Inductive reactance increases & Current decreases

so V across inductor decreases

Unfortunately, this cannot be the correct answer. It is contradictory in itself. Please check whether you have transcribed this incorrectly.

You haven't answered lightgrav's question: does this problem involve a series R + C or a series R + L. You have mentioned both, probably a careless mistake due to haste, or you may be mixing up two separate questions.

 

[rude man]

You did not describe the position of the inductor in the circuit.