Inequality b*(b-4)<-4a is there a way to find the restrictions

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The discussion revolves around solving the inequality b*(b-4)<-4a and finding the restrictions on variables a and b. It is established that the inequality can be rewritten as a quadratic inequality: a < (-1/4)b(b - 4). The solution involves graphing the equation a = (-1/4)(b^2 - 4b), which represents a downward-opening parabola. The solution set lies either inside or outside the parabola, determined by testing a point not on the graph. If the inequality holds for that point, the solution set is on that side; otherwise, it is on the opposite side. The discussion also touches on a more complex inequality involving b and a, questioning the feasibility of satisfying both inequalities simultaneously.
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Mathematica or Maple

If I have an inequality b*(b-4)<-4a is there a way to find the restrictions on a and b for which inequality holds?
 
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This can be done without Mathematica or Maple.

b(b - 4) < -4a <==> (-1/4)b(b - 4) > a

This is a quadratic inequalilty. To find the solution set, graph a = (-1/4)(b^2 - 4b). The graph is a parabola that opens down. The graph of the parabola isn't in the solution set, but one side or another (i.e., either the inside or outside) of the parabola represents the solution set.

To determine which side is the solution set, simply pick any point that is not on the graph of the parabola. If the original inequality is a true statement for that point, the solution set is all of the points on that side of the parabola. If the original inequality is not a true statement for that point, the solution set is all of the points on the other side.
 


What if I had to satisfy another inequality?

b^2/a^2-2*b/a+2*b+1-2*a+a^2 > 0, a-b < 0
 
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Wait, is this ever possible?

b < a-a^2, a+a^2 < b ?
 


Nevermind.
 
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