A pendulum consists of a uniform thin rod of mass 5 kg and length 2 m to which is fixed a circular disc of mass 8 kg and radius 0.4 m. There is a pivot at one end. (a) Find the CoM and Moment of Inertia when the disc is: (i) half way along the rod; (ii) at the opposite end of the rod to the pivot. I cannot do part i. I found the moment of inertia of the rod to be I = (1/3)ML^2 I = 1/3*5*2^2 I = 6.667 kgm^2 but I don't know how to calculate for the disc. For part ii. I found the CoM using M = ((5*1)+(8*2))/13 M = 1.62m from pivot I found Inertia using: I = (1/12)ML^2 +(1/2)MR^2+ML^2 I = 5.507 kgm^2 Have I got the correct answer for part ii? How would I calculate for part i? Also, how would I find angular velocity given angular impulse? Any help greatly appreciated.