Infinite Sheet Potential Question

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CH1991
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Homework Statement



Please check picture below or attachment.

http://i.imgur.com/DayoP.png

Diagram of two thin parallel infinite charged sheets separated by distance d, the left sheet marked +σ and the right sheet marked -σ, with a multiple-choice question below asking for the potential difference V+σ - V-σ and options a, b and c.


Homework Equations



E=density/2 constant

The Attempt at a Solution



I know, E=density/2 constant, but how do we get potential from eletric field and how do I find it is positive or negative?

Thanks!
 
Attachments
  • Diagram of two parallel thin infinite sheets separated by d = 1.5 cm, the left sheet labelled +σ and the right sheet -σ, with a multiple-choice question on the potential difference between them and options a) ΔV = -σd/ε0, b) ΔV = -σd/2ε0, c) ΔV = σd/ε0; the answer given is c.
    2.png
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Recall that the electric field strength is negative gradient of the potential which is equivalent to say the potential difference VA-VB between points A and B is[tex]V_B-V_A=-\int_A^B{E_s ds}[/tex]
Find the electric field between the plates first.

ehild
 
Yeah,I did find E=density/2 constant as my eletric field, but how do I get potential?
Thanks!
 
CH1991 said:
Yeah,I did find E=density/2 constant as my eletric field, but how do I get potential?
Thanks!

That is the electric field from the charge distribution of one plate, but you have two plates.

You need the potential difference between the plates.
Have you read my previous post how to get the potential difference?

ehild