Infinite Subsets: Length & Terms Explained

  • Thread starter Thread starter jason177
  • Start date Start date
  • Tags Tags
    Infinite Subsets
jason177
Messages
24
Reaction score
0
Alright this is a pretty simple question. So if A is a infinite subset of the reals, does that mean that its length is infinite (eg. the set of all numbers from 0 to infinite) or could it also be just a set with an infinite number of terms (eg. the set of all real numbers between 1 and 2)?
 
Physics news on Phys.org
jason177 said:
Alright this is a pretty simple question. So if A is a infinite subset of the reals, does that mean that its length is infinite (eg. the set of all numbers from 0 to infinite)
No.
or could it also be just a set with an infinite number of terms (eg. the set of all real numbers between 1 and 2)?
Yes.In fact its length could be zero.
 
jason177 said:
Alright this is a pretty simple question. So if A is a infinite subset of the reals, does that mean that its length is infinite (eg. the set of all numbers from 0 to infinite) or could it also be just a set with an infinite number of terms (eg. the set of all real numbers between 1 and 2)?

Everyone's favorite counter example to everything: The Cantor Set.

Let C be the Cantor set. C is a subset of the unit interval. After you remove C from the unit interval, the length of what is left in the unit interval is 1, so the length of C is 0. At the same time, there are the same number of points in C as there are left in the unit interval, so C is infinite. C is an odd little set, you should check it out.
 
alright, thank you both for your replies
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top