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Initial conditions for stability

  1. Nov 4, 2006 #1
    The general solution fo the following equations:

    x'=2x-3y
    y'=x-2y

    Is, x=4C1e^2t, y=C1e^2t-3C2e^-2t

    They ask for me to list a set of initial conditions (xo, yo) for which the solution is stable, i.e, (x, y)-->(0,0) for large t.

    I don't understand this part of the problem.
     
  2. jcsd
  3. Nov 4, 2006 #2

    Office_Shredder

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    Basically, for what constants C1 and C2 do x and y go to infinity as t gets large? From that, solve for what x(0) and y(0) can be
     
  4. Nov 8, 2006 #3
    Ok, I understand that for the general solution, the only unstable part of it is e^-2t. What does the setup of the solution look like?
     
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