- #1
Jamiemma1995
- 8
- 0
I'm working on some stuff for particle physics and I had a few questions I wanted to ask .
Heres the outline of the problem :
Establish which initial states of the ppbar system amongst 1^S_0, 3^S_1, 1^P_1, 3^P_0, 3^P_1, 3^P_2, 1^D_2, 3^D_1, 3^D_2, 3^D_3
the reaction ppbar->npi^0 can proceed for a) any n , b) n=2
Here are my questions
1) would I be correct in saying that this is a strong interaction because particle -antiparticle reactions are governed by the strong interaction which then means that Isospin is conserved and so as ppbar has isospin I=0 or 1 then the pion system must also have I= 0 or 1 and so we can limit which initial states are possible using this fact ?
2) I know that the parity of a proton is 1 , and so its antiparticle has parity -1 then I think that we can say that the parity of the ppbar system is
P(ppbar)=(1)(-1)^l where l is the total angular momentum of the ppbar system , is that right ?
3) pi^0 is a psuedoscalar so it has parity -1 which would then give the parity for n=2 case as P(pi^0pi^0)= (-1)(-1)^J=(-1)^(J+1) , where J = l+S , then extending this to the case where n is any number we could say that P(npi^0)= (-1)^(J+n-1), is this correct ?
4) my final question is about the notation of the atomic orbitals (I've never had to use them before , I do physics not chemistry ) say we have 1^S_0, Then I think what this means is that the superscript on the lhs indicates that it's a singlet and the subscript on the rhs tells us that its total orbital angular momentum is 0 , I'm not sure if that's correct though...additionally is there any further information we can take from knowing for instance that the ppbar starts in say the 1^S_0 state ?
Heres the outline of the problem :
Establish which initial states of the ppbar system amongst 1^S_0, 3^S_1, 1^P_1, 3^P_0, 3^P_1, 3^P_2, 1^D_2, 3^D_1, 3^D_2, 3^D_3
the reaction ppbar->npi^0 can proceed for a) any n , b) n=2
Here are my questions
1) would I be correct in saying that this is a strong interaction because particle -antiparticle reactions are governed by the strong interaction which then means that Isospin is conserved and so as ppbar has isospin I=0 or 1 then the pion system must also have I= 0 or 1 and so we can limit which initial states are possible using this fact ?
2) I know that the parity of a proton is 1 , and so its antiparticle has parity -1 then I think that we can say that the parity of the ppbar system is
P(ppbar)=(1)(-1)^l where l is the total angular momentum of the ppbar system , is that right ?
3) pi^0 is a psuedoscalar so it has parity -1 which would then give the parity for n=2 case as P(pi^0pi^0)= (-1)(-1)^J=(-1)^(J+1) , where J = l+S , then extending this to the case where n is any number we could say that P(npi^0)= (-1)^(J+n-1), is this correct ?
4) my final question is about the notation of the atomic orbitals (I've never had to use them before , I do physics not chemistry ) say we have 1^S_0, Then I think what this means is that the superscript on the lhs indicates that it's a singlet and the subscript on the rhs tells us that its total orbital angular momentum is 0 , I'm not sure if that's correct though...additionally is there any further information we can take from knowing for instance that the ppbar starts in say the 1^S_0 state ?