Inner product of random Gaussian vector

AI Thread Summary
The discussion centers on the inner product of a random Gaussian vector and a constant vector. It is confirmed that if a random vector X follows a multivariate normal distribution, the inner product with a constant vector d will also yield a normally distributed result. This supports the initial intuition that the Gaussian distribution remains unchanged through this operation. The inner product can be viewed as a linear transformation, which preserves the Gaussian nature of the distribution. Therefore, the source distribution remains Gaussian after the inner product is taken.
architect
Messages
30
Reaction score
0
Hi,

I would like to ask a question please.

Assume we have a random vector X that is distributed under the Gaussian model and take the inner product of this vector and another constant vector d. Will the source distribution (Gaussian) remain the same? My intuition (although I might be wrong) says yes since the inner product may be regarded as a scaling operation. I know that this is true when we multiply a random variable with a constant, I just wonder if it applies to the inner product as well.

BR,

Alex.
 
Last edited:
Physics news on Phys.org
architect said:
Hi,

I would like to ask a question please.

Assume we have a random vector X that is distributed under the Gaussian model and take the inner product of this vector and another constant vector d. Will the source distribution (Gaussian) remain the same? My intuition (although I might be wrong) says yes since the inner product may be regarded as a scaling operation. I know that this is true when we multiply a random variable with a constant, I just wonder if it applies to the inner product as well.

BR,

Alex.

By definition if a random vector x=x_1+x_2+...+x_n has a multivariate normal distribution, then the inner product y=<a,x>, where a is a constant vector:

y=a_{1}x_{1}+a_{2}x_{2},+...+a_{n}x_{n} is normally distributed.
 
Last edited:
Thanks for your help. Appreciated!

BR,

Alex
 
I was reading documentation about the soundness and completeness of logic formal systems. Consider the following $$\vdash_S \phi$$ where ##S## is the proof-system making part the formal system and ##\phi## is a wff (well formed formula) of the formal language. Note the blank on left of the turnstile symbol ##\vdash_S##, as far as I can tell it actually represents the empty set. So what does it mean ? I guess it actually means ##\phi## is a theorem of the formal system, i.e. there is a...

Similar threads

Back
Top