Integral for the calculation of torque

Click For Summary
SUMMARY

The integral for calculating torque from applied torsional shear stress is expressed as T = ∫τ⋅r⋅dA = ∫τ⋅2πr⋅dr. This formula indicates that torque (T) is derived from the shear stress (τ) multiplied by the distance (r) from the center and the differential area (dA). The integral sums the contributions of each infinitesimal area, accounting for their respective distances from the center, which is crucial for accurate torque calculation.

PREREQUISITES
  • Understanding of torque and its physical significance
  • Familiarity with shear stress concepts
  • Basic knowledge of integral calculus
  • Experience with differential area calculations
NEXT STEPS
  • Study the derivation of torque equations in mechanics
  • Explore applications of shear stress in engineering contexts
  • Learn about the role of integrals in calculating physical quantities
  • Investigate the relationship between torque and rotational dynamics
USEFUL FOR

Students and professionals in mechanical engineering, physics enthusiasts, and anyone interested in the mathematical foundations of torque calculations.

laurajk
Messages
2
Reaction score
0
Hello,
I found an integral to calculate the torque from the applied torsional shear stress, and I didn't find an explanation of how this integral is deviated. Where does it come from? Could someone explain?

T = ∫τ⋅r⋅dA = ∫τ⋅2πr⋅dr,
where T is the torque and τ the shear stress.

Thanks a lot!
 
Physics news on Phys.org
laurajk said:
integral is deviated.
I think you mean derived.:smile: And welcome to PF.

Do you understand how force is stress times area? Torque is similar, except that you need to include the distance from center. The torque contribution of an infinitesimal area is proportional to the distance from center, so a simple multiplication does not work. The integral is summing up the contribution of each infinitesimal area times its distance from the center. That's your first equation: Tau is stress, dA is area, and r is distance from center, and the integral adds it all up over the entire area.

Hope this helps.
 
Hello!
Yes, it should be derived, of course :)
And thank you very much for your explanation, it's very helpful and I think, I got it now! :)
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K