Integral involving partial fractions and roots

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SUMMARY

The discussion focuses on solving integrals involving partial fractions, specifically addressing the challenge of factoring denominators correctly. The user mentions extracting a constant (272) from the integral, leading to the expression u/(u(u+4)). The primary issue arises in correctly applying partial fraction decomposition, where the user struggles with the cancellation of common factors. The conversation emphasizes the importance of factoring the denominator to simplify the integral effectively.

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  • Understanding of integral calculus concepts
  • Familiarity with partial fraction decomposition techniques
  • Knowledge of algebraic manipulation, including factoring polynomials
  • Experience with basic integration methods
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  • Study the process of partial fraction decomposition in detail
  • Practice factoring polynomials to prepare for integration
  • Learn about common integral forms and their applications
  • Explore advanced integration techniques, such as integration by parts
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Students and educators in calculus, mathematicians focusing on integral calculus, and anyone looking to improve their skills in solving integrals involving partial fractions.

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PS. Just wanted to say thanks for all the help so far. This is a really great forum and I am receiving tons of help. I like how people here are not just blurting the answers, but are actually feeding me ideas so that I may work them out. Everyone here is really helping me learn this stuff! Thanks again. :smile:
 
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Well, you forgot to do partial fractions! (e.g. you didn't factor the denominator...)
 
:-p haha... I know the demoninator is not factored there. I just left the equation like that so it was complete for the posting. I know I have to factor it and do the whole partial fractions bit, but this is where my problem lies.

For example, what I have on paper is that I took the 272 out of the integral, which left u/(u(u+4)) inside the integral.

But then the partial fractions do not come out right for me.
 
There is a common factor of u in both the numerator and denominator of that fraction, cancel it out and then it should be a very simple integral.
 

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