Integral of E dot dA - conceptual

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SUMMARY

The integral of the electric field vector E = 4i and the area vector A = 2i + 3j leads to the calculation of electric flux, represented as Φ = ∫ E · dA. The correct interpretation of dA is as a vector differential of area, which is perpendicular to the surface being integrated over. The final result of the integral is Φ = 8 flux units, calculated by the dot product of E and A. This problem highlights the importance of understanding vector calculus in the context of electric flux.

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quantum13
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Homework Statement


A = 2i + 3j
E = 4i

determine the integral of E dot dA

Homework Equations


Integral calculus, vectors

The Attempt at a Solution


I don't understand why one could do this. The integral is of E and dA, not E and A. How can I use A to determine dA? Do I take its derivative? Then I would only get dA = 0.Also: This is part of an electric flux problem. Is this a basic of multivariate calculus? I'm indecisive on whether or not I should get a MV calc textbook - I don't have one yet, but I don't want basic questions like this holding me back either. I'm studying from Halliday's Fundamentals of Physics which apparently isn't a calculus heavy text.
 
Last edited:
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the question isn't very celar, but here's my 2 cents...

E is the electric field vector

Generally A represent some surface or area A. dA is vector in the direction normal to surface. If n is a unit vector in that direction, dA is a scalar infintesimal area, then

\texbf{dA} = \textbf{n}dA
with
A = \int dA

For a vector field E, the flux is given by
\Phi = \int \textbf{E} \bullet \textbf{dA}

physically the dot product means if the vector is parallel to the surface its contribution is zero, or maximum when it is perpindiuclar to the surface (passing through it). The integral just sums all the contributions across the whole surface.

so is there anymore to make the question clearer?
what area do you integrate over?
A is given as a vector - does this represent a normal to a plane or something?
 
quantum13 said:

Homework Statement


A = 2i + 3j
E = 4i

determine the integral of E dot dA

Homework Equations


Integral calculus, vectors


The Attempt at a Solution


I don't understand why one could do this. The integral is of E and dA, not E and A. How can I use A to determine dA? Do I take its derivative? Then I would only get dA = 0.


Also: This is part of an electric flux problem. Is this a basic of multivariate calculus? I'm indecisive on whether or not I should get a MV calc textbook - I don't have one yet, but I don't want basic questions like this holding me back either. I'm studying from Halliday's Fundamentals of Physics which apparently isn't a calculus heavy text.
You are right. The problem as stated makes no sense. I suggest you go back and reread the problem. It may be that you have overlooked something. "dA" should be a "vector differential of area" of some surface, not just a vector. Are you not given a surface to integrate over?
 
I'm sorry. dA is in fact an area vector perpendicular to a surface. However, the surface is definitely not stated. The answer is given as 8 (flux units). Does it make any mathematical sense to do this?

\Phi = \int \vec{E} \cdot \vec{dA}

<br /> \Phi = \vec{E} \cdot \int \vec{dA} <br />

<br /> \Phi = \vec{E} \cdot \vec{A} <br />Then
Phi = (4i) dot (2i + 3j)
= 8

No clue if this makes any sense or not but...?
 
Last edited:

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