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## Homework Statement

∫5/(4x√(9-16x

^{2})dx

## Homework Equations

I am pretty sure this is in the form of ∫du/(u√(a

^{2}-u

^{2})

## The Attempt at a Solution

setting u=4x a=3 and du=4dx so 1/4du=dx I get:

-5/12 sech

^{-1}(4x/3) + C

Is this right or am I using the wrong definition? Just trying to check my answers

Thanks for any help