Integral of inverse trig or inverse hyperbolic

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SUMMARY

The integral ∫5/(4x√(9-16x²)dx can be solved using the substitution method, specifically setting u=4x and a=3, leading to the result -5/12 sech⁻¹(4x/3) + C. This solution confirms the correct application of the integral form ∫du/(u√(a²-u²). Additionally, the discussion raises a pertinent question regarding the conditions a>u or u>a in the context of indefinite integrals, emphasizing the importance of understanding these definitions for accurate problem-solving.

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  • Understanding of integral calculus, specifically integration techniques.
  • Familiarity with hyperbolic functions and their inverses.
  • Knowledge of substitution methods in integration.
  • Concept of limits of integration in definite integrals.
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  • Study the properties and definitions of hyperbolic inverse functions.
  • Learn about the application of substitution in solving integrals.
  • Explore the differences between definite and indefinite integrals.
  • Investigate advanced techniques in integral calculus, such as integration by parts.
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Students and educators in calculus, mathematicians focusing on integral calculus, and anyone seeking to deepen their understanding of hyperbolic functions and their applications in integration.

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Homework Statement



∫5/(4x√(9-16x2)dx

Homework Equations



I am pretty sure this is in the form of ∫du/(u√(a2-u2)

The Attempt at a Solution



setting u=4x a=3 and du=4dx so 1/4du=dx I get:

-5/12 sech-1(4x/3) + C

Is this right or am I using the wrong definition? Just trying to check my answers

Thanks for any help
 
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Yes, that is correct.
 
Thanks, I really appreciate it!

One quick follow-up question to anyone who can help:

Some of the integral definitions involving hyperbolic inverse functions call for if a>u or u>a. I know that dealing with a definite integral we just use the limits of integration to figure that out, but what if we are dealing with an indefinite integral? How do you know then?
 

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