1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Integral of inverse trig or inverse hyperbolic

  1. Nov 17, 2011 #1
    1. The problem statement, all variables and given/known data

    ∫5/(4x√(9-16x2)dx

    2. Relevant equations

    I am pretty sure this is in the form of ∫du/(u√(a2-u2)

    3. The attempt at a solution

    setting u=4x a=3 and du=4dx so 1/4du=dx I get:

    -5/12 sech-1(4x/3) + C

    Is this right or am I using the wrong definition? Just trying to check my answers

    Thanks for any help
     
  2. jcsd
  3. Nov 18, 2011 #2

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Yes, that is correct.
     
  4. Nov 18, 2011 #3
    Thanks, I really appreciate it!

    One quick follow-up question to anyone who can help:

    Some of the integral definitions involving hyperbolic inverse functions call for if a>u or u>a. I know that dealing with a definite integral we just use the limits of integration to figure that out, but what if we are dealing with an indefinite integral? How do you know then?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Integral of inverse trig or inverse hyperbolic
Loading...