renob
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Homework Statement
[tex]\int1/sqrt(1-(x+1)^2) dx[/tex]
2. The attempt at a solution
I think a=1 but don't know what to set u equal to.
The integral of the inverse trigonometric function discussed is represented as ∫1/√(1-(x+1)²) dx. The user initially struggled with determining the appropriate substitution for u but later clarified that a=1 is correct. This integral can be solved using trigonometric substitution, specifically by setting u = x + 1, which simplifies the expression under the square root.
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