∫(x+1)/(x^2 + 4x +5) dx
Anyone can help me doing it using Arctan and ln
Let's first hear out your own idea to solve this problem? What strategy you have in mind?
∫(x+1)/(x^2+4x+5) dx = 1/2∫ (2x+2)/(x^2+4x+5) dx = 1/2∫(2x+4)/(x^2+4x+5) dx + 1/2∫(-2)/(1+(x+2)^2) dx
[1/2 ln l(x^2+4x+5)l ] - arctan(x+2)
Don't forget the "constant of integration".
Try re-writing the original expression into something more manageable.
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