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Integral of (x+1)/(x^2+4x+5)

  1. Jan 27, 2016 #1
    • Member warned about posting homework questions in a technical forum section
    ∫(x+1)/(x^2 + 4x +5) dx
    Anyone can help me doing it using Arctan and ln
     
  2. jcsd
  3. Jan 27, 2016 #2

    blue_leaf77

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    Let's first hear out your own idea to solve this problem? What strategy you have in mind?
     
  4. Jan 27, 2016 #3
    ∫(x+1)/(x^2+4x+5) dx = 1/2∫ (2x+2)/(x^2+4x+5) dx = 1/2∫(2x+4)/(x^2+4x+5) dx + 1/2∫(-2)/(1+(x+2)^2) dx
    [1/2 ln l(x^2+4x+5)l ] - arctan(x+2)
    SO??
     
  5. Jan 27, 2016 #4

    HallsofIvy

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    Don't forget the "constant of integration".
     
  6. Jan 27, 2016 #5
    Thaanks
     
  7. Jan 29, 2016 #6

    phion

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    Try re-writing the original expression into something more manageable.
     
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