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I shall prove that this integral is uniformly convergent or not:
and if it is convergent, i must describe its uniform convergence
and if it is convergent, i must describe its uniform convergence
There was a mistake in my previous reply, I(0) is of course zero.So, one more time, this is what i'm doing - i'm inspecting for uniform convergence:
[tex] $\int_{0}^{\infty}{\frac{\sqrt{\alpha}}{\sqrt{{\alpha}^{2}x^{4}+1}}dx}$, where $\alpha \in {[0,1]}$
[/tex]
And how do i first evaluate the integral?if you first evaluate the integral and then take the limit you find a different result.