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I'm don't understand a step in the following integral:

*∫(x-1)/(2x+1)dx = ∫(1/2)dx − (3/2)∫1/(2x+1)dx = (1/2)x − (3/4)ln|2x+1| + C*

The first step, where you get the 2 integrals

*∫(1/2)dx*and

*-(3/2)∫1/(2x+1)dx*

Where do

*(1/2)dx*and

*-(3/2)*come from?

And where does

*(3/4)*come from in the last part?

My best guess is that it's done with partial fractions. But even so, I have no clue how.

Thanks in forward,

Young