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I'm don't understand a step in the following integral:

∫(x-1)/(2x+1)dx = ∫(1/2)dx − (3/2)∫1/(2x+1)dx = (1/2)x − (3/4)ln|2x+1| + C

The first step, where you get the 2 integrals∫(1/2)dxand-(3/2)∫1/(2x+1)dx

Where do(1/2)dxand-(3/2)come from?

And where does(3/4)come from in the last part?

My best guess is that it's done with partial fractions. But even so, I have no clue how.

Thanks in forward,

Young

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# Homework Help: Integrals with partial fractions

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