Integrate: 1/(1+2x+x^2) dx

  • Thread starter FUNKER
  • Start date
  • #1
121
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In an exam i stumbled when i saw this q
integrate:
1/(1+2x+x^2) dx
:grumpy:
help
 

Answers and Replies

  • #2
650
1
[tex]\int \frac{dx}{1+2x+x^2}[/tex]

[tex]\int \frac{dx}{(1+x)^2} [/tex]

Whats the pro
 
  • #3
508
1
himanshu121 said:
[tex]\int \frac{dx}{1+2x+x^2}[/tex]

[tex]\int \frac{dx}{(1+x)^2} [/tex]

Whats the pro
?????
?????
 
  • #4
508
1
[tex] 1 + x^2[/tex] + [tex]\frac{1}{3}x^3[/tex]
 
Last edited:
  • #5
591
0
Substitute [itex]u=x+1[/itex]. [itex]du=dx[/itex] so we get

[tex]\int\frac{dx}{(1+x)^2}=\int\frac{du}{u^2}=\int u^{-2}du[/tex]

That should make it a little easier to see what rule you can apply.
 

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