In an exam i stumbled when i saw this q integrate: 1/(1+2x+x^2) dx :grumpy: help
Jul 8, 2004 #1 FUNKER 121 0 In an exam i stumbled when i saw this q integrate: 1/(1+2x+x^2) dx :grumpy: help
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Jul 8, 2004 #2 himanshu121 650 1 [tex]\int \frac{dx}{1+2x+x^2}[/tex] [tex]\int \frac{dx}{(1+x)^2} [/tex] Whats the pro
Jul 9, 2004 #3 gerben 508 1 himanshu121 said: [tex]\int \frac{dx}{1+2x+x^2}[/tex] [tex]\int \frac{dx}{(1+x)^2} [/tex] Whats the pro ????? ?????
himanshu121 said: [tex]\int \frac{dx}{1+2x+x^2}[/tex] [tex]\int \frac{dx}{(1+x)^2} [/tex] Whats the pro ????? ?????
Jul 9, 2004 #5 master_coda 591 0 Substitute [itex]u=x+1[/itex]. [itex]du=dx[/itex] so we get [tex]\int\frac{dx}{(1+x)^2}=\int\frac{du}{u^2}=\int u^{-2}du[/tex] That should make it a little easier to see what rule you can apply.
Substitute [itex]u=x+1[/itex]. [itex]du=dx[/itex] so we get [tex]\int\frac{dx}{(1+x)^2}=\int\frac{du}{u^2}=\int u^{-2}du[/tex] That should make it a little easier to see what rule you can apply.