1. Jul 8, 2004 #1

   FUNKER

   

   In an exam i stumbled when i saw this q
   integrate:
   1/(1+2x+x^2) dx
   :grumpy:
   help

    

   FUNKER, Jul 8, 2004
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3. Jul 8, 2004 #2

   himanshu121

   

   [tex]\int \frac{dx}{1+2x+x^2}[/tex]
   
   [tex]\int \frac{dx}{(1+x)^2} [/tex]
   
   Whats the pro

    

   himanshu121, Jul 8, 2004
4. Jul 9, 2004 #3

   gerben

   

   ?????
   ?????

    

   gerben, Jul 9, 2004
5. Jul 9, 2004 #4

   gerben

   

   [tex] 1 + x^2[/tex] + [tex]\frac{1}{3}x^3[/tex]

    

   Last edited: Jul 9, 2004

   gerben, Jul 9, 2004
6. Jul 9, 2004 #5

   master_coda

   

   Substitute [itex]u=x+1[/itex]. [itex]du=dx[/itex] so we get
   
   [tex]\int\frac{dx}{(1+x)^2}=\int\frac{du}{u^2}=\int u^{-2}du[/tex]
   
   That should make it a little easier to see what rule you can apply.

    

   master_coda, Jul 9, 2004

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