Integrate 1/(x^2 - 2x + 4) using Homework Equations and a Step-by-Step Method

  • Thread starter Thread starter Pyroadept
  • Start date Start date
  • Tags Tags
    Integration
Click For Summary
SUMMARY

The integral of the function ∫[1/(x^2 - 2x + 4)]dx can be solved using the formula ∫[1/(x^2 + a^2)]dx = [1/a](arctan(x/a)) + C. By rewriting the denominator as A = (x - 1)^2 + (√3)^2, the integral simplifies to [1/√3]arctan[(x-1)/√3] + C. This method is confirmed as correct by participants in the discussion.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with arctangent functions
  • Knowledge of completing the square
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of arctangent functions in calculus
  • Learn advanced techniques for integration, such as integration by substitution
  • Explore the method of completing the square in quadratic expressions
  • Practice integrating similar rational functions
USEFUL FOR

Students studying calculus, mathematics educators, and anyone looking to improve their integration skills, particularly with rational functions.

Pyroadept
Messages
82
Reaction score
0

Homework Statement


Integrate the following: ∫[1/(x^2 - 2x + 4)]dx



Homework Equations


∫[1/(x^2 + a^2)]dx = [1/a](arctan(x/a)) + C


The Attempt at a Solution



Let A = x^2 - 2x + 4 = x^2 - 2x + 1 + 3
= (x - 1)^2 + (√3)^2

So ∫[1/A]dx = [1/√3]arctan[(x-1)/√3] + C

Is this correct?

Thanks for any help
 
Physics news on Phys.org
Looks good to me :smile:
 

Similar threads

  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
3K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K