Integrate (1+x+x^2) / x(1+x^2) for x. Partial dractions?

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The discussion focuses on integrating the function (1+x+x^2) / x(1+x^2) using partial fractions. One participant initially claims their result is ln x - 1/2 ln (1-x^2) + arctan x, which is questioned by others. The correct partial fraction expansion is confirmed as A=1, B=0, and C=1, leading to the integral being expressed as the sum of simpler fractions. The final integration yields ln x + arctan x, with a reminder to include the constant of integration. The conversation also touches on the curriculum, questioning whether integration is now included in precalculus courses.
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integre (1+x+x^2) / x(1+x^2)
pls help...
i used partial fraction and obtain the answer of ln x - 1/2 ln (1-x^2) + arctan x
is it correct??
 
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That's not what I get. HOW did you get that? What was the partial fractions expansion?
 
i got 1 +x +x^2 = A(1+x^2) + B(x^2) + Cx
then let x =1 and -1 and again x=0

is it correct??
 
Looks good. So what are your A, B, and C?
Remember that:
\frac{1 + x + x ^ 2}{x(1 + x ^ 2)} = \frac{A}{x} + \frac{Bx + C}{1 + x ^ 2}
What does your final result look like?
 
A=1 B=0 and C=1
 
is it right
 
Yup, it looks good. So:
\int \frac{1 + x + x ^ 2}{x(1 + x ^ 2)} dx = \int \left( \frac{1}{x} + \frac{1}{1 + x ^ 2} \right) dx = ?
Can you integrate this? And what's your answer, then?
 
oh...i intgre wrongly on the above...is should be ln x + arctan x rite??
 
Looks about right, but don't forget the constant of integration. :wink:
 
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Are they teaching integration in precalculus now?:confused:
 
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