Integrate (5x+2)dx/(x-2) from 0 to 1

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Homework Help Overview

The problem involves integrating the function (5x+2)/(x-2) from 0 to 1. The discussion centers around techniques for simplifying the integrand to facilitate integration.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods for simplifying the integrand, including splitting the fraction and using substitution. Some express uncertainty about the next steps after initial attempts.

Discussion Status

Several participants have offered different approaches to rewriting the integrand, suggesting that polynomial division and substitutions may be useful. There is an ongoing exploration of these ideas without a clear consensus on the best method.

Contextual Notes

Participants note the challenge of integrating over the specified limits and the potential need for substitutions or alternative algebraic manipulations. There is an acknowledgment of the complexity involved in the integration process.

erjkism
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Homework Statement



\int\frac{(5x+2)dx}{x-2} from 0 to 1


Homework Equations



The Attempt at a Solution



I've tried splitting it up into (5x)/(x-2) + (2)/x-2), but i couldn't go any farter. Ived also tried using lots of U subsitutions, but i can't figure out what do next. Is there some trick that i am not seeing?
 
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Yep, the obvious one. u=x-2. dx=du. x=2+u.
 
Another way to split it up [without explicitly invoking a substitution]
is to write the numerator 5x+2 as 5(x-2)+12.
 
robphy said:
Another way to split it up [without explicitly invoking a substitution]
is to write the numerator 5x+2 as 5(x-2)+12.
Woah, woulda never thought of that. Nice, I want your vision :-]
 
robphy said:
Another way to split it up [without explicitly invoking a substitution]
is to write the numerator 5x+2 as 5(x-2)+12.

You'll still want u=x-2 to do the 12/(x-2) part.
 
Just do polynomial division. It becomes 5 + 12/(x - 2).

Oops.
 
Dick said:
You'll still want u=x-2 to do the 12/(x-2) part.

True... and now the substitution is really obvious.
 

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