Integrate by Parts: arctan(√x)dx Explained

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SUMMARY

The integral ∫arctan(√x)dx can be solved using the substitution √x=t, leading to the transformation ∫arctan(t)dt2. The confusion regarding the squared dt arises from the differentiation of t², where dx=d(t²)=2tdt. This method employs "integration by substitution" followed by "integration by parts," resulting in the expression 2∫arctan(t)tdt, which is the correct approach for solving the integral.

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Homework Statement


∫arctan(√x)dx.

Using the substitution √x=t:
∫arctan(√x)dx = ∫arctan(t)dt2

This is what I've got written in a solution manual. I don't see why the dt would be squared. Could anyone care explaining me? thanks
 
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The substitution t= \sqrt{x} is the same (for positive x and t) as t^2= x so that dx= d(t^2)= 2tdt.

What is done here is "integration by substitution". The result is 2\int arctan(t) tdt which can now be done by "integration by parts".
 

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