Integrate by Parts: Solving x^13cos(x^7)dx

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SUMMARY

The discussion focuses on solving the integral of x^13 cos(x^7) dx using integration by parts. The user initially struggles with determining the antiderivative of cos(x^7) and correctly applying the integration by parts formula. The solution involves letting u = x^7 and du = 7x^6 dx, transforming the integral into (1/7) ∫ u cos(u) du, which can then be integrated by parts to reach the final answer.

PREREQUISITES
  • Understanding of integration techniques, specifically integration by parts.
  • Familiarity with the concept of antiderivatives.
  • Knowledge of substitution methods in calculus.
  • Basic proficiency in handling trigonometric integrals.
NEXT STEPS
  • Study the integration by parts formula in detail, including its applications.
  • Learn how to find antiderivatives of trigonometric functions, particularly cos(ax).
  • Explore substitution methods for simplifying complex integrals.
  • Practice solving integrals involving polynomial and trigonometric functions together.
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Students and educators in calculus, mathematicians focusing on integration techniques, and anyone looking to enhance their skills in solving complex integrals involving polynomials and trigonometric functions.

punjabi_monster
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Integration by parts :(

hi I have been trying this question for quite a while now and am unsure of what to do. Any help would be apprectiated.

Integral x^13 cos(x^7) dx

I know you have to use integration of parts. Here is what i have done so far:

let U=x^3
dU =13x^12 dx

dV=cos(x^7)
V=?
First off I can't manage to find the antiderivative of cos(x^7)

After finding that i think you use
integral u(dV) = uv - v(dU)
 
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Rewrite the integral as (x^7 * x^6) * cos (x^7). Then let u = x^7. Then du = 7x^6 dx. So the integral becomes:

(1/7) § u cos(u) du

Which you can integrate by parts. Then substitute u back in and you're done.
 

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